Видео

Charge time delay...😢😢😢😅

25000ufvs1000000uf😂

магнитное колдунство?

For some reason, this brute-force derivation always makes my head spin a little, and I've tried to think of it in a way that makes conceptual sense. See what you think of this: The future value (to the bank) of the principal P at maturity is P(1+r)^n. The future value (to the bank) at maturity of the first payment M is M(1+r)^(n-1) because the bank will have that money to loan out for n-1 months. Future value of second payment is M(1+r)^(n-2), and so on until the last payment is worth M when paid at maturity. Since the payments satisfy the loan, you get P(1+r)^n = M(1 + (1+r) + ... + (1+r)^(n-1)). Add the geometric series on the right and get the result.

Excellent teaching tools 👍✌️

But for a conductor the electric field inside is zero and therefore in the case 2 the charge is zero

Какие-то неправильные расчёски 😅

Now lick it.

Los imanes y su campo magnético producen en los conductores cerrados, una corriente inducida que a su vez crean un campo magnético en la misma dirección y sentido al campo de los imanes. En el primer caso, al no existir un circuito cerrado, ya que el peine no cierra sus puas por abajo, la corriente inducida sería casi nula (recorrido muy largo y difícil -> mayor resistencia eléctrica). En el segundo caso, aunque induciremos corriente y generaremos un campo magnético que hace que sus lineas de fuerza creen un iman inaginaro, orientado con los polos para ser atraído por los imanes reales , estará limitado al paso de corriente por los peines, que tienen resistencia. En el ultimo caso al no haber restricciones, la corriente inducida será máxima y la frenada causada por el campo inducido también. Inportante: Para que se produzca corriente inducida en un conductor cerrado, tiene que haber una variación de flujo de las lineas de fuerza del campo magnetico inductor. Es por ello que los transformadores son de corriente alterna o variable.

so to solve a persons sleep in mental health issues can RPM not be calculated in the same pattern

Closed core under Eddy currents and open core Замкнутый сердечник под действием тока и незамкнутый

Such a great and smooth explanation ❤ keep it up

Magnet brake example

Bro can you explain why p1 = p0 -M +p0*r ?

Магнит, аллюминий, токи Фуко.

Congratulations🎉, your videos are really helpful you deserve the award

Де таке купити?

Bring electroBOOM here so it can zap him

Congratulations 🎉

Love from india❤

This is why I chose to go to culinary school😂

How many capacıtor ah,?

Bloody hell

тоесть, без электричества тормозов нет?

I like how comb vs grid explains that there is actual current going through the plates

Question: Why don't we use the relationship that a1=-2(a2) , from differentiating L=(x)1+2(x2) two times. Why don't we include the negative sign?

That was really really helpful, you're awesome

excellent, but i think you should assume that the electric field inside the dielectric is negative to avoid the sign error which is there in the calculations somewhere

I feel like I stumbled upon a pot of gold. You're seriously the greatest. Thank you so much.

Lenz join the chat.

Because C=AE/d A=area E=constant d=plate of capacitor 😊😊😊😊😊😊😊

Okay now do this on a large rotating turntable sitting on an undulating hydraulic platform

Wow! Thank you so much!

Какое покрытие нужно нанести, чтобы третья лопатка болталась как первая?

Thank

Thanks a lot man, even if I am from totally different field and trying to get another job which involves physics, I am getting the hang of these pulleys, slopes etc. thanks to you. Appreciate it

The one on the right has 3 axis...

Where is 4he beef?

you just save me from hell! Thank you HAHHAHAHAHAH

Thank you so much! Finally, a video that used matrices for rotations 😭

I have AB=1ohm, BC=4ohms, CD=5ohms, DA=3ohms and AD=2ohms. Find value of current in branch AB, AD, and BD

Thank you so very much may God bless you sir

You are awesome! You deserve more.. Thank you very much sir.. 1st Comment!

hello Sir in problem 8, isn't the work equal to the force multiplied by the distance so why did you take the variation of the kinetic energy instead of multiplying the force by the distance...

*sigh* the mass of the rocket is changing, the full net force should be m×a+dm/dt×v

Поздравляю вы изобрели велосипед!

al primo non l'avevo afferrato che attraversava due magneti

Hi, I appreciate your ways of solving those problems. However, I think, the question a) of Example 5 is a bit imprecise: You ask: what is the force for lowering the weight with constant speed of 2 m/s and your answer is m/2*g. The answer is principally correct because a=0 and v=const. But, if you apply this force, nothing would move, if I assume that tha weight was at rest. So, you first have to decrease this force to a value lower than m/2*g to produce an acceleration. Then the weight is accelerated from v=0 to a velocity different from zero. If the speed of the weight has reached v = 2 m/s due to this acceleration, then you can change the force to m/2*g and now v=const=2 m/s. In numbers: If you apply a force of m/4*g then the acceleration is -5 m/s^2 and it takes 0.4 s to reach v=2 m/s. If you apply 80% of m/2*g= 0.4*m*g, then a = - 2 m/s^2 and it takes 1 second to reach v=2 m/s.

Пластик и два металла.

Micro adjust by turning the screw hooks. Better would be, drill holes in top board and run string through holes with "cork/plug".